x^2+7x+42=3x

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Solution for x^2+7x+42=3x equation: 



x^2+7x+42=3x

We move all terms to the left:

x^2+7x+42-(3x)=0

We add all the numbers together, and all the variables

x^2+4x+42=0

a = 1; b = 4; c = +42;
Δ = b2-4ac
Δ = 42-4·1·42
Δ = -152
Delta is less than zero, so there is no solution for the equation

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